Set umask to 000 and create a regular file using the common requested mode 0666.
Assume no default ACL.
What mode is created?
umask only removes permissions from the requested mode. Even with umask 000, a regular file requested as 0666 does not gain execute bits.
Detailed explanation
0777Incorrect. 0777 is a directory-style mode and cannot be produced from the 0666 request by umask.
Incorrect. 0777 is a directory-style mode and cannot be produced from the 0666 request by umask.
0666Correct. With umask 000, the requested regular-file mode remains 0666.
Correct. With umask 000, the requested regular-file mode remains 0666.
0600Incorrect. 0600 would require additional masking.
Incorrect. 0600 would require additional masking.
0000Incorrect. umask 000 does not remove every permission.
Incorrect. umask 000 does not remove every permission.
Try it yourself
An example you can run in a temporary verification environment.
umask 000; umaskExpected result
0000Key points
- Regular-file base mode is 0666
- umask is a removal mask
- It never adds execute bits
Notes
- Environment: Bash 5.2／POSIX umask
- Command output formatting can vary slightly by distribution or tool version.
- Run the example in a temporary directory or process when possible.
Foundation review
Read the scope first
Check whether the command acts on the current shell, a new process, an existing process, or a file.
Verify the observable result
Use the supplied command and compare the output with the expected result.