Showing a unit's journal | LinuC Level 1 102 Exam original practice question

1.09.2Basic

Filter journal entries produced by nginx.service.

Which command is appropriate?

Hint 1: Focus on the requirement

Identify what must change and what must remain unchanged. Then choose the command whose scope matches that requirement.

Hint 2: Check each command's role

Separate commands that display information, change state, remove data, or affect a child process.

journalctl -u nginx.service: Correct. -u nginx.service selects the unit's journal entries.
journalctl -t nginx.service: Incorrect. -t filters a syslog identifier.
journalctl -p nginx.service: Incorrect. -p selects priority.
journalctl -k nginx.service: Incorrect. -k selects kernel messages.

Detailed explanation

Correctjournalctl -u nginx.service

Correct. -u nginx.service selects the unit's journal entries.

Incorrectjournalctl -t nginx.service

Incorrect. -t filters a syslog identifier.

Incorrectjournalctl -p nginx.service

Incorrect. -p selects priority.

Incorrectjournalctl -k nginx.service

Incorrect. -k selects kernel messages.

An example you can run in a temporary verification environment.

journalctl --help | grep -E -- '-u|--unit' | head -n 1

unit filterのhelp行

Foundation review

Check whether the command acts on the current shell, a new process, an existing process, or a file.

Use the supplied command and compare the output with the expected result.

Question IDKL-102-1094

Environmentsystemd journalctl help / journal読取なし

Last technical review2026-08-13