Find the network address for host 192.168.10.130/26.
Which address is the network address?
A /26 has blocks of 64; 130 lies in 128-191, so the network is 192.168.10.128.
Detailed explanation
192.168.10.0Incorrect. That is the /24 boundary.
Incorrect. That is the /24 boundary.
192.168.10.64Incorrect. 64-127 does not contain 130.
Incorrect. 64-127 does not contain 130.
192.168.10.128Correct. The /26 block containing 130 starts at 128.
Correct. The /26 block containing 130 starts at 128.
192.168.10.192Incorrect. 192 starts the next block.
Incorrect. 192 starts the next block.
Try it yourself
An example you can run in a temporary verification environment.
python3 -c "import ipaddress; print(ipaddress.ip_interface('192.168.10.130/26').network.network_address)"Expected result
192.168.10.128Key points
- /26 block size 64
- 130 is in 128-191
- Zero host bits
Notes
- Environment: Python 3 ipaddress
- Command output formatting can vary slightly by distribution or tool version.
- Run the example in a temporary directory or process when possible.
Foundation review
Read the scope first
Check whether the command acts on the current shell, a new process, an existing process, or a file.
Verify the observable result
Use the supplied command and compare the output with the expected result.